1884 United States presidential election in Connecticut
(Redirected from United States presidential election in Connecticut, 1884)
The 1884 United States presidential election in Connecticut took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose six representatives, or electors to the Electoral College, who voted for president and vice president.
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Connecticut voted for the Democratic nominee, Grover Cleveland, over the Republican nominee, James G. Blaine. Cleveland won the state by a very narrow margin of 0.94%. Cleveland was the first Democrat to win without New London County since 1844 and Middlesex County since 1832.
Results
| 1884 United States presidential election in Connecticut[1] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | Grover Cleveland of New York | Thomas Andrews Hendricks of Indiana | 67,182 | 48.95% | 6 | 100.00% | ||
| Republican | James Gillespie Blaine of Maine | John Alexander Logan of Illinois | 65,898 | 48.01% | 0 | 0.00% | ||
| Prohibition | John Pierce St. John of Kansas | William Daniel of Maryland | 2,493 | 1.82% | 0 | 0.00% | ||
| Greenback | Benjamin Franklin Butler of Massachusetts | Absolom Madden West of Mississippi | 1,684 | 1.23% | 0 | 0.00% | ||
| Total | 137,257 | 100.00% | 6 | 100.00% | ||||