Samarium(III) molybdate is an inorganic compound, with the chemical formula Sm2(MoO4)3. It is one of the compounds formed by the three elements samarium, molybdenum and oxygen.
    | |
| Identifiers | |
|---|---|
| Properties | |
| Sm2(MoO4)3 | |
| Appearance | white solid[1] |
| insoluble | |
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa). | |
Preparation
Samarium(III) molybdate can be obtained by reacting samarium(III) nitrate and sodium molybdate in the pH range of 5.5~6.0.[2] Its single crystal can be grown at 1085 °C by the Czochralski method.[3]
Samarium(III) molybdate can also be prepared by reacting samarium and molybdenum(VI) oxide:
Properties
Samarium(III) molybdate forms violet crystals of several modifications:
- orthorhombic crystal system, space group P ba2, unit cell parameters a = 1.04393 nm, b = 1.04794 nm, c = 1.07734 nm, Z = 4, exists at temperatures below 193°C.
- monoclinic crystal system, exists at temperatures above 193°C.[4][5]
Samarium(III) molybdate exhibits ferroelectric properties.[6] It forms a crystalline hydrate with the composition Sm2(MoO4)3•2H2O.
Samarium(III) molybdate can be reduced to the tetravalent molybdenum compound Sm2Mo3O9 by hydrogen at 500~650 °C.[7]