The 2019 Jacksonville mayoral election was held on March 19, 2019, to elect the mayor of Jacksonville. Incumbent mayor Lenny Curry, a Republican, won a majority of votes to win a second term in office.[2] No Democratic candidate qualified for the mayoral election.[3]
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| Turnout | 24%[1] | ||||||||||||||||||||||||||||||||||
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 Results by precinct Curry: 30–40% 40–50% 50–60% 60–70% 70–80% 80–90% Brosche: 30–40% 40–50% | |||||||||||||||||||||||||||||||||||
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Candidates
Republican Party
Declared
- Lenny Curry, incumbent mayor[4]
- Anna Brosche, member of Jacksonville City Council[5]
- Jimmy Hill, small business owner and president of International Association of Fire Fighters Local 2622[6]
Democratic Party
While Democratic candidates did declare their candidacy, no Democratic candidates qualified for the mayoral election in 2019.
Declared
- Doreszell Cohen, founder of Citizens for Criminal Justice Reform[7]
- Yolanda Thornton, small business owner[8]
Declined
- Alvin Brown, former mayor of Jacksonville[9]
- Garrett Dennis, member of Jacksonville City Council[6][10]
Independents
Declared
Campaign and results
Democrats did not field a candidate for Mayor of Jacksonville in the 2019 election. Curry faced Anna Lopez Brosche, described by The Florida Times-Union as a moderate Republican. Brosche's campaign received support from some Democratic politicians, including city councilman Garrett Dennis and former Duval County Democratic Party chair Lisa King.[3]
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | Lenny Curry (incumbent) | 84,545 | 57.62 | |
| Republican | Anna Lopez Brosche | 35,404 | 24.13 | |
| Independent | Omega Allen | 15,453 | 10.53 | |
| Republican | Jim Hill | 11,056 | 7.54 | |
| write-in | Michael Romero | 263 | 0.18 | |
| Total votes | 146,721 | 100.00 | ||
| Republican hold | ||||
References
| Preceded by 2015 | Jacksonville mayoral election 2019 | Succeeded by 2023 |
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