2018 Boyd Tinsley Clay Court Classic – Doubles

Jovana Jakšić and Catalina Pella were the defending champions, but decided not to participate.

Doubles
2018 Boyd Tinsley Clay Court Classic
Final
ChampionsUnited States Sophie Chang
United States Alexandra Mueller
Runners-upUnited States Ashley Kratzer
United States Whitney Osuigwe
Score3–6, 6–4, [10–7]
Events
SinglesDoubles
← 2017 ·Boyd Tinsley Clay Court Classic· 2019 →

Sophie Chang and Alexandra Mueller won the title after defeating Ashley Kratzer and Whitney Osuigwe 3–6, 6–4, [10–7] in the final.

Seeds

Draw

Key

Draw

First roundQuarterfinalsSemifinalsFinal
1 I Bara
M Duque Mariño
66
  K Cartwright
K Pierre-Louis
311 I Bara
M Duque Mariño
27[10]
WC A Smith
N Subhash
66WC A Smith
N Subhash
65[5]
  M Mateas
R Yurovsky
241 I Bara
M Duque Mariño
64[4]
3 S Chang
A Mueller
663 S Chang
A Mueller
16[10]
  L Chirico
F Di Lorenzo
333 S Chang
A Mueller
76
  P Januskova
R Ozaki
46[7] C Rosatello
AS Sánchez
52
  C Rosatello
AS Sánchez
63[10]3 S Chang
A Mueller
36[10]
  V Duval
J Loeb
64[10] A Kratzer
W Osuigwe
64[7]
  Q Gleason
A Weinhold
26[8] V Duval
J Loeb
662[10]
  A Kratzer
W Osuigwe
66 A Kratzer
W Osuigwe
377[12]
4 PC Gonçalves
S Marand
34 A Kratzer
W Osuigwe
62[12]
  J Cristian
K Day
13 I Neel
M Sanchez
46[10]
  I Neel
M Sanchez
66 I Neel
M Sanchez
61[20]
  R McAdoo
K Stewart
64[7]2 A Guarachi
E Routliffe
26[18]
2 A Guarachi
E Routliffe
26[10]

References