1956 French Championships – Men's doubles

The 1956 French Championships men's doubles was one of the competitions of the 1956 French Championships, a tennis tournament held at the Stade Roland-Garros in Paris, France from 15 May until 26 May 1956. The matches were played in a best-of-five sets format. Don Candy and Bob Perry defeated Ashley Cooper and Lew Hoad 7–5, 6–3, 6–3 in the final to win the title. The winning teams received 25,000 French franc per player with the runner-up players earning 12,000 Fr and the four losing semifinalists receiving 6,000 Fr each.[2][3][4]

Men's doubles
1956 French Championships
Final
ChampionAustralia Don Candy
United States Bob Perry[1]
Runner-upAustralia Ashley Cooper
Australia Lew Hoad[1]
Score7–5, 6–3, 6–3
Details
Draw32
Events
Singlesmenwomen
Doublesmenwomen
← 1955 ·French Championships· 1957 →

Draw

Finals

QuarterfinalsSemifinalsFinal
                     
Nicola Pietrangeli
Orlando Sirola
3744
Don Candy
Bob Perry
6566
Don Candy
Bob Perry
63119
Luis Ayala
Sven Davidson
3697
Luis Ayala
Sven Davidson
4666
Gordon Forbes
Ian Vermaak
6444
Don Candy
Bob Perry
766
Ashley Cooper
Lew Hoad
533
Andrés Gimeno
Fernando Olazaga
525
Jaroslav Drobný
Trevor Fancutt
767
Jaroslav Drobný
Trevor Fancutt
428
Ashley Cooper
Lew Hoad
6610
Jacques Brichant
Gino Mezzi
113
Ashley Cooper
Lew Hoad
666

References