1886 Georgia gubernatorial election

The 1886 Georgia gubernatorial election was held on 6 October 1886 in order to elect the Governor of Georgia. Democratic nominee, former United States Senator from Georgia and candidate for Governor in the 1868 election John B. Gordon ran unopposed and thus won the election.[1]

1886 Georgia gubernatorial election

← 18846 October 18861888 →
 
NomineeJohn B. Gordon
PartyDemocratic
Popular vote101,159
Percentage99.20%

Governor before election

Henry Dickerson McDaniel
Democratic

Elected Governor

John B. Gordon
Democratic

General election

On election day, 6 October 1886, Democratic nominee John B. Gordon won the election with 99.20% of the vote, thereby holding Democratic control over the office of Governor. Gordon was sworn in as the 53rd Governor of Georgia on 9 November 1886.[2]

Results

Georgia gubernatorial election, 1886
PartyCandidateVotes%
DemocraticJohn B. Gordon 101,159 99.20
Others8150.80
Total votes101,974 100.00
Democratic hold

References