1869 Ohio gubernatorial election

The 1869 Ohio gubernatorial election was held on October 12, 1869. Incumbent Republican Rutherford B. Hayes defeated Democratic nominee George H. Pendleton with 50.74% of the vote.

1869 Ohio gubernatorial election

← 1867October 12, 18691871 →
 
NomineeRutherford B. HayesGeorge H. Pendleton
PartyRepublicanDemocratic
Popular vote236,082228,581
Percentage50.74%49.13%

County results
Hayes:      50–60%      60–70%      70–80%      80–90%
Pendleton:      50–60%      60–70%      70–80%

Governor before election

Rutherford B. Hayes
Republican

Elected Governor

Rutherford B. Hayes
Republican

General election

Candidates

  • Rutherford B. Hayes, incumbent Governor (Republican)
  • George H. Pendleton, former U.S. Representative from Cincinnati, nominee for Vice President of the United States in 1864, and candidate for President in 1868 (Democratic)
  • Samuel Scott (Prohibition)

Results

1869 Ohio gubernatorial election[1]
PartyCandidateVotes%±%
RepublicanRutherford B. Hayes (incumbent) 236,082 50.74%
DemocraticGeorge H. Pendleton228,58149.13%
ProhibitionSamuel Scott6290.14%
Majority7,501
Turnout
Republican holdSwing

References