1788–89 United States presidential election in Georgia

The 1788–89 United States presidential election in Georgia took place on January 7, 1789 as part of the 1788–89 United States presidential election. The state legislature chose 5 representatives, or electors to the Electoral College, who voted for President and Vice President.

1788–89 United States presidential election in Georgia

January 7, 17891792 →
 
NomineeGeorge WashingtonJohn MiltonJames Armstrong
PartyIndependentIndependentIndependent
Home stateVirginiaGeorgiaGeorgia
Electoral vote521
Percentage100.00%

 
NomineeEdward TelfairBenjamin Lincoln
PartyIndependentIndependent
Home stateGeorgiaMassachusetts
Electoral vote11

President before election

Office established

Elected President

George Washington
Independent

George Handley, John King, George Walton, Henry Osborne, and John Milton served as electors. The electors cast five votes for George Washington, two for Milton, one for James Armstrong, one for Edward Telfair, and one for Benjamin Lincoln.[1]

References

Works cited

  • Jensen, Merrill; Becker, Robert, eds. (1976). The First Federal Elections 1788-1790: Congress, South Carolina, Pennsylvania, Massachusetts, New Hampshire. Vol. 1. University of Wisconsin Press. ISBN 0299066908.


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